To Stop a Process that is Waiting on socket.accept()

mumebuhi mumebuhi at gmail.com
Fri Oct 27 07:25:13 CEST 2006


I am having problem to kill the following script completely. The script
basically does the following. The main thread creates a new thread,
which does a completely useless thing, and then starts excepting for a
connection via socket.

# start
import pickle
import signal
import simplejson
import socket
import sys
import threading
import time

counter = 0

class WorkerThread(threading.Thread):
	def run(self):
		global counter
		while True:
			counter += 1
			time.sleep(10)

worker_thread = WorkerThread()
worker_thread.start()

server = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
server.bind(('', 2727))
server.listen(2)

def cleanup(signal, frame):
	print "die now"
	worker_thread.join(1)
	server.shutdown(socket.SHUT_RDWR)
	sys.exit(0)
signal.signal(signal.SIGINT, cleanup)

while True:
	channel, details = server.accept()
	stats = { 'key': "value" }
	s = simplejson.dumps(stats)
	channel.send(s)
	channel.close()
# end

The way I can think of right now is to kill the script using Ctrl+C.
Hence, the signal handler in the code. However, the interpreter
complains:
---start---
Traceback (most recent call last):
  File "ex_server.py", line 35, in ?
    channel, details = server.accept()
  File "/usr/lib/python2.4/socket.py", line 169, in accept
    sock, addr = self._sock.accept()
  File "ex_server.py", line 30, in cleanup
    server.shutdown(SHUT_RDWR)
NameError: global name 'SHUT_RDWR' is not defined
---end---

Can anybody suggest a better way to do this?

Thank you.


Buhi




More information about the Python-list mailing list