urllib.urlopen: Errno socket error

Salvatore salvatore.didio at wanadoo.fr
Mon Oct 16 20:31:14 CEST 2006


Hello,

Try to increase the time out : socket.settimeout(n)
and catch the timeout error when it occurs

Regards



kgrafals at gmail.com a écrit :

> Hi,
>
> I'm just trying to read from a webpage with urllib but I'm getting
> IOErrors. This is my code:
>
> import urllib
> sock = urllib.urlopen("http://www.google.com/")
>
> and this is the error:
>
> Traceback (most recent call last):
>   File "<pyshell#5>", line 1, in <module>
>     sock = urllib.urlopen("http://www.google.com/")
>   File "C:\Python25\lib\urllib.py", line 82, in urlopen
>     return opener.open(url)
>   File "C:\Python25\lib\urllib.py", line 190, in open
>     return getattr(self, name)(url)
>   File "C:\Python25\lib\urllib.py", line 325, in open_http
>     h.endheaders()
>   File "C:\Python25\lib\httplib.py", line 856, in endheaders
>     self._send_output()
>   File "C:\Python25\lib\httplib.py", line 728, in _send_output
>     self.send(msg)
>   File "C:\Python25\lib\httplib.py", line 695, in send
>     self.connect()
>   File "C:\Python25\lib\httplib.py", line 679, in connect
>     raise socket.error, msg
> IOError: [Errno socket error] (10060, 'Operation timed out')
>
> I'm behind my company's firewall. Would that cause a problem? If it
> does, How do I get around it?




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