How do I read Excel file in Python?
giles_brown at hotmail.com
Fri Oct 6 12:22:39 CEST 2006
John Machin wrote:
> houdinihound at yahoo.com wrote:
> > > > >>> excel_date = 38938.0
> > > > >>> python_date = datetime.date(1900, 1, 1) + datetime.timedelta(days=excel_date)
> > > > >>> python_date
> > > > datetime.date(2006, 8, 11)
> > >
> > > Err, that's the wrong answer, isn't it? Perhaps it shoud be
> > > datetime.date(1900, 1, 29)?
> > Actually was about to post same solution and got same results. (BTW
> > Simon, the OP date is Aug 9th, 2006). Scratched head and googled for
> > excel date calculations... found this bug where it treats 1900 as leap
> > year incorrectly:
> > http://www.ozgrid.com/Excel/ExcelDateandTimes.htm
> > Plus it treats 1 jan 1900 as day 1, not 0 so just subtract 2 in the
> > calc:
> > >>>python_date = datetime.date(1900, 1, 1) + datetime.timedelta(days=excel_date - 2)
> > >>> python_date
> > datetime.date(2006, 8, 9)
> ... and 2006-08-09 is only the correct answer if the spreadsheet was,
> when last saved, using the 1900 ("Windows") date system, not the 1904
> ("Macintosh") date system.
Just for me own curiosity, is this Excel concept of date numbers same
as the OLE
concept (see http://msdn2.microsoft.com/en-us/library/82ab7w69.aspx or
search "MFC DATE" on MSDN).
I put in some test cases for conversion code here:
But would be interested to add any additional info on variations on
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