Plotting histograms

[amitsoni.1984 at gmail.com]

Thanks for the replies  ... its perfect now ... but just one more thing
... how can I plot another function(a semi circle) in the same
histogram?

thanks

amit


Robert Kern wrote:
> amitsoni.1984 at gmail.com wrote:
> > Thanks Robert,
> >
> > My previous problem is solved(I was using 'from matplotlib.pylab import
> > *') but now I am facing another problem. I want to plot the histogram
> > of eigenvalues calculated and I am using the following code:
> > _______________________________________________________________________
> > import numpy
> > from matplotlib import pylab
> >
> > n=100
> > ra = numpy.random
> > la = numpy.linalg
> >
> > A = ra.standard_normal((n,n))
> > S = (A + numpy.transpose(A))/(2*n^(1/2))
>
> Note that this line won't do what you think it does. First, one integer divided
> by another integer returns an integer, so (1/2) == 0. Also, ^ is not
> exponentiation but bitwise XOR. Use ** for exponentiation. However, in this
> case, you should use numpy.sqrt().
>
> > eig = la.eigvals(S)
> >
> > [N,x]=pylab.hist(eig, 10) # make a histogram
> > -------------------------------------------------------------------------------------------------------------
> >
> > But again it is giving some error, which is given below:
> >
> > File "C:\Documents and Settings\amitsoni\Desktop\New
> > Folder\wignerpython", line 15, in <module>
> > [N,x]=pylab.hist(eig, 10) # make a histogram
> > ValueError: too many values to unpack
> >
> > Can anyone help me out with this??
>
> pylab.hist() does not return two values, it returns three. Sorry I didn't catch
> that earlier.
>
> --
> Robert Kern
>
> "I have come to believe that the whole world is an enigma, a harmless enigma
>   that is made terrible by our own mad attempt to interpret it as though it had
>   an underlying truth."
>    -- Umberto Ec