MIMEMultipart() and CRLF vs RFC 2046
alf
ask at me
Thu Oct 5 17:52:41 EDT 2006
Hi,
according to rfc2046, line breaks in MIME are CRLF. However python just
uses LF like in the following example:
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
msg = MIMEMultipart()
msg['Subject'] = 'Our family reunion'
msg['From'] = 'a at a.b'
msg['To'] = 'c at x.y'
msg.epilogue = ''
msg.attach(MIMEText('aaaaaaaaaaaaaaaaaaaaaaaa'))
print `msg.as_string()`
gives:
'Content-Type: multipart/mixed;
boundary="===============1018679223=="\nMIME-Version: 1.0\nSubject: Our
family reunion\nFrom: a at a.b\nTo:
c at x.y\n\n--===============1018679223==\nContent-Type: text/plain;
charset="us-ascii"\nMIME-Version: 1.0\nContent-Transfer-Encoding:
7bit\n\naaaaaaaaaaaaaaaaaaaaaaaa\n--===============1018679223==--\n'
Any insight why does it not stick to standard. I also checked parsing
and it seems to accept both CRLF and LF.
--
Thx, alfz1
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