stdout not flushed before os.execvp()
fulvio at pc.jaring.my
Wed Oct 18 09:34:12 CEST 2006
On Wednesday 18 October 2006 00:25, Fredrik Lundh wrote:
> |feature. the "exec" system call operates on a lower level than the
> |stdio buffering system.
I did in this manner:
for exe in ('imap4', 'pop3'):
if exe in cfgfil[optsrv + '.protocol']:
exe = exe[:4]; exe = 'call_func = _call_' + exe.upper() \
call_func = '#ERROR 02 = Protocol failed with %s' %optsrv
exists it a different way to do it?
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