the first arg to super() must be a type, not a class obj?

[Georg Brandl]

metaperl wrote:
> On p.282 of "Python Cookbook" and in the Python docs on calling super:
> http://www.python.org/download/releases/2.2.3/descrintro/#cooperation
> 
> it is clear that the first argument to super is a class and not a type.
> However, for the code below, I am getting an error when attempting to
> provide a class as my first argument and don't understand why. Also,
> since this is my first attempt at writing anything of any seriousness
> in Python, any other feedback is welcome.

"super" only works for new-style classes.

You could make "ftputilx" new-style by inheriting from object and FTPHost,
but FTPHost is still old-style, and I don't know if that's okay with super.

So in your case it would be advisable to use

FTPHost.__init__(self)

instead of

super(ftputilx, self).__init__()

Georg