Problems with email.Generator.Generator

[Manlio Perillo]

Chris Withers ha scritto:
> Hi All,
> 
> The following piece of code is giving me issues:
> 
> from email.Charset import Charset,QP
> from email.MIMEText import MIMEText
> charset = Charset('utf-8')
> charset.body_encoding = QP
> msg = MIMEText(
>     u'Some text with chars that need encoding: \xa3',
>     'plain',
>     )
> msg.set_charset(charset)
> print msg.as_string()
> 
> Under Python 2.4.2, this produces the following output, as I'd expect:
> 

> [...]
> However, under Python 2.4.3, I now get:
> 

Try with:

msg = MIMEText(
     u'Some text with chars that need encoding: \xa3',
     _charset='utf-8',
     )


and you will obtain the error:


Traceback (most recent call last):
  File "<pyshell#4>", line 3, in -toplevel-
    _charset='utf-8',
  File "C:\Python2.4\lib\email\MIMEText.py", line 28, in __init__
    self.set_payload(_text, _charset)
  File "C:\Python2.4\lib\email\Message.py", line 218, in set_payload
    self.set_charset(charset)
  File "C:\Python2.4\lib\email\Message.py", line 260, in set_charset
    self._payload = charset.body_encode(self._payload)
  File "C:\Python2.4\lib\email\Charset.py", line 366, in body_encode
    return email.base64MIME.body_encode(s)
  File "C:\Python2.4\lib\email\base64MIME.py", line 136, in encode
    enc = b2a_base64(s[i:i + max_unencoded])
UnicodeEncodeError: 'ascii' codec can't encode character u'\xa3' in
position 41: ordinal not in range(128)




Regards  Manlio Perillo