How to get the package, file, and line of a method/function invocant?

Marc 'BlackJack' Rintsch bj_666 at
Tue Sep 12 08:33:15 CEST 2006

In <1158038477.221439.15260 at>, metaperl wrote:

> # Of course I could cheat and pass it, but I don't want to:
> directories =

Why do you consider a plain and simple solution cheating?

	Marc 'BlackJack' Rintsch

More information about the Python-list mailing list