Converting a varargs tuple to a list - a definite pitfall for new comers to Python
g.brandl-nospam at gmx.net
Fri Sep 15 07:02:28 CEST 2006
metaperl.etc at gmail.com wrote:
> The following program does not work if you uncomment #lis =
> ["xmms2"] + list(args)
> Evidently Python is opting for the nullary constructor list() as
> opposed to the other one which takes a sequence. But no newcomer would
> know this. And the Python docs dont give a good example of dealing with
> taking a sequence of args and converting it to a list.
Evidently you overlooked having defined a list() in global scope
yourself which takes no arguments.
> I must've spent 40 minutes looking through my ora books, googling and
> irc'ing in vane on this.
> import subprocess
> def xmms2(*args):
> #lis = ["xmms2"] + list(args)
> lis = ["xmms2"] + [a for a in args]
> output = subprocess.Popen(lis,
> return output.splitlines()
> def list():
This is called by list(args) above, and the call fails.
If you want to avoid such clashes, don't name your functions list,
dict, int, str etc.
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