itertools.count(-3)
bearophileHUGS at lycos.com
bearophileHUGS at lycos.com
Thu Sep 21 10:51:02 EDT 2006
itertools.count docs say:
Does not currently support python long integers.
Note, count() does not check for overflow and will return negative
numbers after exceeding sys.maxint. This behavior may change in the
future.
But it seems it doesn't support negative numbers too:
>>> from itertools import count, islice
>>> list(islice(count(), 0, 5))
[0, 1, 2, 3, 4]
>>> list(islice(count(10), 0, 5))
[10, 11, 12, 13, 14]
>>> list(islice(count(-3), 0, 5))
[4294967293L, 4294967294L, 4294967295L, 0, 1]
>>> def count2(n=0):
... while True:
... yield n
... n += 1
...
>>> list(islice(count2(-3), 0, 5))
[-3, -2, -1, 0, 1]
If this isn't a bug, then maybe docs can tell about this too.
Bye,
bearophile
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