SWIG, Python, C++, and Coca-Cola

bressert at gmail.com bressert at gmail.com
Fri Apr 6 21:15:32 CEST 2007


Hi Everyone,

Recently I have been working on building a module for Python from C++
code, with SWIG, and towards the end of compiling the various sets of
code I'm getting an error.

[comp:~/swig_project] user% swig -c++ -python example.i
[comp:~/swig_project] user% g++ -c example.cpp
[comp:~/swig_project] user% g++ -c example_wrap.cxx -I/scisoft/i386/
Packages/Python-2.4.3/Python.framework/Versions/2.4/include/python2.4/
example_wrap.cxx: In function 'PyObject* _wrap_main(PyObject*,
PyObject*)':
example_wrap.cxx:735: error: 'main' was not declared in this scope


The beginning of example.i looks like the following:

%module filename
%{
#define file_plugin "plugins/file.h"
#if foo_OS!=2
#include <pthread.h>
#endif
#include "../Foo.h"
using namespace foo_library;
%}


The error that is being picked up in reference to 'main'  is contained
in the following excerpt, generated by SWIG (example_wrap.cxx):


/*-----------------------------------------------
              @(target):= _filename.so
  ------------------------------------------------*/
#define SWIG_init    init_filename

#define SWIG_name    "_filename"

#define cimg_plugin "plugins/file.h"
#if foo_OS!=2
#include <pthread.h>
#endif
#include "../Foo.h"
using namespace foo_library;

#ifdef __cplusplus
extern "C" {
#endif
static PyObject *_wrap_main(PyObject *self, PyObject *args) {
    PyObject *resultobj;
    int arg1 ;
    char **arg2 = (char **) 0 ;
    int result;
    PyObject * obj1 = 0 ;

    if(!PyArg_ParseTuple(args,(char *)"iO:main",&arg1,&obj1)) goto
fail;
    if ((SWIG_ConvertPtr(obj1,(void **) &arg2,
SWIGTYPE_p_p_char,SWIG_POINTER_EXCEPTION | 0 )) == -1) SWIG_fail;
    result = (int)main(arg1,arg2);

    resultobj = PyInt_FromLong((long)result);
    return resultobj;
    fail:
    return NULL;
}

Any clues as to what is happening here or what to do next? If you
know, your help would greatly help. Thanks in advance!




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