way to extract only the message from pop3

Collin Stocks collinstocks at gmail.com
Thu Apr 5 20:09:18 CEST 2007


so get two strings: only headers, and the whole message.
find the length of the headers, and chop that off the beginning of the whole
message:

message=whole_message[len(headers):None]


You can omit the word None: it is just there for clarity purposes.


On 3 Apr 2007 12:36:10 -0700, flit <superflit at gmail.com> wrote:
>
> Hello All,
>
> Using poplib in python I can extract only the headers using the .top,
> there is a way to extract only the message text without the headers?
>
> like remove the fields below:
> "
> Return-Path:
> X-Original-To:
> Received: from [
>         by (Postfix) with ESMTP id B32382613C
>         for  Tue,  3 Apr 2007 09:54:28 -0300 (BRT)
> Date: Tue, 03 Apr 2007 09:52:15 -0300
> From:  <@>
> To:
> Subject: test
> Message-Id:
> MIME-Version: 1.0
> Content-Type: text/plain; charset="US-ASCII"
> Content-Transfer-Encoding: 7bit
> X-Mailer: Becky! ver. 2.24.02 [en]
> X-UIDL: !Dn!!HKT!!/k
> Status: RO
> "
> and only get this:
>
> this is a text message..
> ..
>
> Thanks
>
> --
> http://mail.python.org/mailman/listinfo/python-list
>
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