Reading the first line of a file (in a zipfile)

Gabriel Genellina gagsl-py2 at yahoo.com.ar
Wed Apr 11 22:10:50 CEST 2007


En Wed, 11 Apr 2007 16:13:42 -0300, <mike.aldrich at gmail.com> escribió:

> Hi folks,
> I am trying to read the first occurence of non-whitespace in a file,
> within a zipfile. Here is my code:
>
> zipnames = glob.glob("<search_dir>*")
> for zipname in zipnames:
>   z = zipfile.ZipFile(zipname, "r")
>   for filename in z.namelist():
>     count = len(z.read(filename).split('\n'))
>     if fnmatch.fnmatch(filename, "*AUDIT*"):
>       test = filename.split(' ')
>       print 'File:', test[0],
>       bytes = z.read(filename)
>       print 'has', len(bytes), 'bytes'
>       print 'and', count, 'lines'
>
> The first line in the file I am examining will be a number followed by
> more whitespace. Looks like I cannot split by whitespace?

Your code does nothing with the first line on the file; you only split the  
*filename* on whitespace. And you extract the file twice.
You don't even try to find "the first occurence of non-whitespace". Surely  
an example of file contents and what output you really expect from it  
would be adequate.

-- 
Gabriel Genellina



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