way to extract only the message from pop3

[Tim Williams]

On 06/04/07, Tim Williams <tim at tdw.net> wrote:

> Content: ['text/plain', 'text/html', 'message/delivery-status',
> 'text/plain', 'text/plain', 'text/plain', 'unknown', 'message/rfc822',
> 'text/plain', 'text/html']

I should explain that this was the content in a single email

>
> # part.get_content_maintype() requires a further call
> # to get_content_subtype() , so use
> # part.get_content_type() instead.
>
> required = ['text/plain', 'text/tab-separated-values']
> for part in EMAIL_OBJ.walk():
>     text_parts = []
>     if part.get_content_type() in required:
>          text_parts.append(part)
>
>     print ('\r\n' + '='*76 +'\r\n').join(text_parts)
>     # print all the text parts seperated by a line of '='
> # end

Content: ['text/plain', 'text/html', 'message/delivery-status',
'text/plain', 'text/plain', 'text/plain', 'unknown', 'message/rfc822',
'text/plain', 'text/html']

Is text/html  a text part or an html part for this exercise ?  :)

You need to walk the parts and use something like

# part.get_content_maintype() requires a further call
# to get_content_subtype() , so use
# part.get_content_type() instead.

required = ['text/plain', 'text/tab-separated-values']
for part in EMAIL_OBJ.walk():
   # text_parts = []   <==  oops, this should be above the for.....
   if part.get_content_type() in required:
        text_parts.append(part)

   print ('\r\n' + '='*76 +'\r\n').join(text_parts)
   # print all the text parts seperated by a line of '='
# end