How to open a txt file from the same folder as my module (w/out changing the working dir)
sergio.correia at gmail.com
Thu Apr 5 01:03:01 CEST 2007
I have a program in 'C:\Python25\Lib\site-packages\spam\spam.py'
Importing and everything works fine:
>>> from spam import spam
But the program calls a file located on the same folder (that is:
How do i do that?
Traceback (most recent call last):
File "<pyshell#21>", line 1, in <module>
datita = spam.eggs()
File "C:\Python25\lib\site-packages\spam\spam.py", line 149, in JustDoIt
config = open("configuration.txt", "rb").read().split('\r\n')
IOError: [Errno 2] No such file or directory: 'configuration.txt'
My last resort is to hard code the path for that file, but it's ugly,
and I want to know if I'm missing something. Am I?
Thanks a lot,
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