(no) fast boolean evaluation ?

[Paddy]

On Aug 4, 5:33 pm, Paddy <paddy3... at googlemail.com> wrote:
> On Aug 4, 4:18 pm, Paddy <paddy3... at googlemail.com> wrote:
>
>
>
> > On Aug 2, 10:47 pm, Stef Mientki <S.Mientki-nos... at mailbox.kun.nl>
> > wrote:
>
> > > hello,
>
> > > I discovered that boolean evaluation in Python is done "fast"
> > > (as soon as the condition is ok, the rest of the expression is ignored).
>
> > > Is this standard behavior or is there a compiler switch to turn it on/off ?
>
> > > thanks,
> > > Stef Mientki
>
> > The following program shows a(clumsy)? way to defeat the short-
> > circuiting:
>
> > def f(x):
> >   print "f(%s)=%s" % ('x',x),
> >   return x
> > def g(x):
> >   print "g(%s)=%s" % ('x',x),
> >   return x
>
> > print "\nShort circuit"
> > for i in (True, False):
> >   for j in (True, False):
> >     print i,j,":", f(i) and g(j)
>
> > print "\nShort circuit defeated"
> > for i in (True, False):
> >   for j in (True, False):
> >     print i,j,":", g(j) if f(i) else (g(j) and False)
>
> > The output is:
>
> > Short circuit
> > True True : f(x)=True g(x)=True True
> > True False : f(x)=True g(x)=False False
> > False True : f(x)=False False
> > False False : f(x)=False False
>
> > Short circuit defeated
> > True True : f(x)=True g(x)=True True
> > True False : f(x)=True g(x)=False False
> > False True : f(x)=False g(x)=True False
> > False False : f(x)=False g(x)=False False
>
> > - Paddy.
>
> And here are the bits for boolean OR:
>
> print "\n\nShort circuit: OR"
> for i in (True, False):
>   for j in (True, False):
>     print i,j,":", f(i) or g(j)
>
> print "\nShort circuit defeated: OR"
> for i in (True, False):
>   for j in (True, False):
>     print i,j,":", (g(j) or True) if f(i) else g(j)
>
> - Paddy.

Dumb!
 Use & and |
Gosh That port last night was good ;-)