Syntax Question - list multiplication
Thomas Jollans
thomas at jollans.com
Sun Aug 19 18:40:40 EDT 2007
On Sunday 19 August 2007, Pablo Torres wrote:
> Hi guys!
>
> I am working on Conway's Game of Life right now and I've run into a
> little problem.
>
> I represent dead cells with 0s and live ones with 1s. Check this out:
> >>> grid = [[0] * 3] * 3
> >>> grid
>
> [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
>
> >>> grid[0][0] = 1
>
> [[1, 0, 0], [1, 0, 0], [1, 0, 0]]
>
> Now, that's not what I want. I just want the first element of the
> first sublist to be a 1, not the first of every one. Here's what I
> tried and didn't work:
>
> 0. grid = [[0] * 3][:] * 3 then the same grid[0][0] = 1 statement
> 1. grid = [[0][:] * 3] * 3 followed by the same assignment
> 2. (grid[0])[0] = 1 with the original initialization of the grid
>
> So, that means that it isn't a problem with two different variables
> refering to the same list (0. and 1. prove that). What I don't
> understand is why 2. doesn't work either. I'm baby-feeding my
> instructions to Python and the mistake is still there. Any ideas?
If you want three copies of the list, you need to copy it thrice (well, twice)
Thus:
>>> row = [0] * 3
>>> grid = []
>>> for n in xrange(3): grid.append(row[:])
...
>>> grid
[[0, 0, 0], [0, 0, 0], [0, 0, 0]]
>>> grid[0][0] =1
>>> grid
[[1, 0, 0], [0, 0, 0], [0, 0, 0]]
>>>
--
Regards, Thomas Jollans
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