Performance on local constants?
William McBrine
wmcbrine at users.sf.net
Sat Dec 22 05:53:39 EST 2007
Hi all,
I'm pretty new to Python (a little over a month). I was wondering -- is
something like this:
s = re.compile('whatever')
def t(whatnot):
return s.search(whatnot)
for i in xrange(1000):
print t(something[i])
significantly faster than something like this:
def t(whatnot):
s = re.compile('whatever')
return s.search(whatnot)
for i in xrange(1000):
result = t(something[i])
? Or is Python clever enough to see that the value of s will be the same
on every call, and thus only compile it once?
--
09 F9 11 02 9D 74 E3 5B D8 41 56 C5 63 56 88 C0 -- pass it on
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