SystemError: new style getargs format but argument is not a tuple
zefciu
zefirek at Speacock.Pau.Apoznan.Mpl
Mon Feb 26 15:33:51 EST 2007
Ziga Seilnacht wrote:
> The second example uses your approach and is a bit more cumbersome,
> but still works. Could you post your current version of the code?
> I don't understand where your problem could be.
I think, there's no need to. Now I understand :)
> if (!PyArg_ParseTuple(args, "Oid", &coord,
> &iteration_number, &bailoutsquare))
There was no ampersand in my version before coord. I thought that as
coord is already a pointer, PyArg_ParseTuple will want it, not the
pointer to the pointer.
Now it works, but I will of course change it to get the simpler
parenthesised version as in your Example 1.
Great thanks :D
zefciu
More information about the Python-list
mailing list