How to use time.clock() function in python

samuel.y.l.cheung at gmail.com samuel.y.l.cheung at gmail.com
Tue Jan 23 00:32:58 CET 2007


Thanks.

I have a fuction called 'func1'.

def func1:
     # logic of the function

When my script just call 'func1()' it works.
func1()

But when put it under timerit.Timer, like this:
t = timeit.Timer("func1()","")
t.repeat(1, 10)

# want to time how long it takes to run 'func1' 10 times, I get an
error like this:
  File "/usr/lib/python2.4/timeit.py", line 188, in repeat
    t = self.timeit(number)
  File "/usr/lib/python2.4/timeit.py", line 161, in timeit
    timing = self.inner(it, self.timer)
  File "<timeit-src>", line 6, in inner
NameError: global name 'func1' is not defined

I don't understand why i can't find 'func1', when I call the function
'func1' directly, it works.
but why when I call it within 'timeit', it can't find it?

Thank you.





Gabriel Genellina wrote:
> At Monday 22/1/2007 19:05, yinglcs at gmail.com wrote:
>
> >I am following this python example trying to time how long does an
> >operation takes, like this:
> >
> >My question is why the content of the file (dataFile) is just '0.0'?
> >I have tried "print >>dataFile, timeTaken" or "print >>dataFile,str(
> >timeTaken)", but gives me 0.0.
> >Please tell me what am I missing?
> >
> >
> >         t1 = time.clock()
> >         os.system(cmd)
> >
> >         outputFile = str(i) + ".png"
> >
> >         t2 = time.clock()
> >
> >         timeTaken = t2 - t1
> >         allTimeTaken += timeTaken
> >         print >>dataFile, timeTaken
>
> time.clock() may not give you enough precision; see this recent post
> http://mail.python.org/pipermail/python-list/2007-January/422676.html
> Use the timeit module instead.
>
>
> --
> Gabriel Genellina
> Softlab SRL
>
>
>
>
>
>
> __________________________________________________
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