regex question
Paul McGuire
ptmcg at austin.rr._bogus_.com
Mon Jan 8 03:44:20 EST 2007
"proctor" <12cc104 at gmail.com> wrote in message
news:1168243020.304940.212700 at 42g2000cwt.googlegroups.com...
>
>
> it does work now...however, one more question: when i type:
>
> rx_a = re.compile(r'a|b|c')
> it works correctly!
>
Do you see the difference between:
rx_a = re.compile(r'a|b|c')
and
rx_a = re.compile("r'a|b|c'")
There is no difference in the variable datatype between "string" and "raw
string". Raw strings are just a notational helper when creating string
literals that have lots of backslashes in them (as happens a lot with
regexps).
r'a|b|c' is the same as 'a|b|c'
r'\d' is the same as '\\d'
There is no reason to "add raw strings" to your makeRE method, since you
don't have a single backslash anywhere. And even if there were a backslash
in the 'w' argument, it is just a string - no need to treat it differently.
-- Paul
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