Module name to filename and back?
rrr at ronadam.com
Thu Jan 18 23:12:17 CET 2007
Ron Adam wrote:
> Is there a function to find a filename from a dotted module (or package) name
> without importing it?
> The imp function find_module() doesn't work with dotted file names. And it
> looks like it may import the file as it raises an ImportError error exception if
> it can't find the module. (Shouldn't it raise an IOError instead?)
> What I'm looking for is to be able to get the full module name when I have a
> filename. And get the full filename when I have the module name. And do both
> of these without importing the module.
> modulename <==> filename
> filename <==> modulename
I found a partial answer in trace.py. It has a fullmodname() function, but it
doesn't do any validation so the name it returns is a guess. Starting with it I
tried to make it a bit more complete, but it still needs work. Seems like there
should be an easier way.
""" Get module or package name from a path name.
Return None if path is invalid, or name is not a
valid (reachable) package or module.
path = os.path.normcase(path)
if not os.path.exists(path):
path = path[:-1]
longest = ""
for dir in sys.path:
dir = os.path.normcase(dir) + os.sep
if len(dir) > len(longest):
longest = dir
base = path[len(longest):]
# should check if in current dir?
return # path not in search sys.path
# This need a bit more work, it should also check
# for valid parent packages too.
valid = False
for ext in ['.py', '.pyc', '.pyo']:
if os.path.isfile(os.path.join(path, '__init__' + ext)):
valid = True
base, ext = os.path.splitext(base)
name = base.replace(os.sep, ".")
name = name.replace(os.altsep, ".")
path = "c:\\python25\\lib\\xml\\sax\\handler.py"
prints --> xml.sax.handler
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