Fastest way to convert a byte of integer into a list

Paul Rubin http
Fri Jul 13 03:05:54 CEST 2007

John Machin <sjmachin at> writes:
> > numlist = lookup_table[num]
> > where lookup_table is a precomputed list of lists.
> Ummm ... didn't the OP say he had 32-bit numbers???

He asked about 8 bit numbers.  I saw something about 32-bit numbers
but figured those would be split into bytes or something:  
(untested and I don't remember if this is the byte order wanted):

from itertools import chain
numlist = list(chain(lookup_table[(num>>i)&0xff] for i in xrange(0,32,8)))

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