pythonic parsing of URL
Green.Horn.000 at gmail.com
Sat Jul 28 05:10:32 CEST 2007
I get some string as below from a library method (qt3
QDropEvent.data()) I use.
I need file path on my system, for the above example:
C:/Documents and Settings/Username/My Documents/45-61-Abc fold-
I am doing the below, it doesn't look pythonic,
can someone suggest any elegant solution, which is not too cryptic to
understand? yep, I do care about readability of the code to average
python user :)
tmpTuple = urlparse.urlparse(fileURLname)
tmpString = tmpTuple.strip('/\\')
fileName = urllib.unquote(tmpString)
#For some reason the string contained in 'fileName' has some
unprintable trailing characters, Any ideas on that?
#thus I do below
fileName = fileName.split('.vru') + '.vru'
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