yield keyword usage
steve at holdenweb.com
Tue Jul 31 02:47:57 CEST 2007
> coulde any one show me the usage of "yield" keyword specially in this
> """Fibonacci sequences using generators
> This program is part of "Dive Into Python", a free Python book for
> experienced programmers. Visit http://diveintopython.org/ for the
> latest version.
> __author__ = "Mark Pilgrim (mark at diveintopython.org)"
> __version__ = "$Revision: 1.2 $"
> __date__ = "$Date: 2004/05/05 21:57:19 $"
> __copyright__ = "Copyright (c) 2004 Mark Pilgrim"
> __license__ = "Python"
> def fibonacci(max):
> a, b = 0, 1
> while a < max:
> yield a
> a, b = b, a+b
> for n in fibonacci(1000):
> print n,
A function body with at least one yield expression (formerly a yield
statement) in its body returns a generator when called:
>>> def gen(i):
... for k in range(i):
... yield k*k
>>> g = gen(3)
<generator object at 0x7ff2822c>
The same function can be called multiple times to create independent
generators - the particular example I have given created a generator for
a given number of squares.
The generator can be used in an iterative context (such as a for loop),
but in actual fact it observes the Python iterator protocol, so the
generator has a .next() method, which can be used to extract the next
value from it. Calling the .next() method runs the generator until a
yield expression is encountered, and the value of the yield expression
is the return value of the next method:
When the generator function terminates (either with a return statement
or by dropping off the end) it raises a StopIteration exception. This
will terminate an iteration, but in other contexts it can be handled
just like any other exception:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
So the fibonacci example you quote is a generator function that will
yield a sequence of Fibonacci numbers up to but not including the value
of its argument.
Steve Holden +1 571 484 6266 +1 800 494 3119
Holden Web LLC/Ltd http://www.holdenweb.com
Skype: holdenweb http://del.icio.us/steve.holden
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