os.path.isfile()

[7stud]

On Jul 1, 3:36 am, Duncan Booth <duncan.bo... at invalid.invalid> wrote:
> 7stud <bbxx789_0... at yahoo.com> wrote:
> > Here is a program to print out the files in a directory:
>
> > -----------
> > import os
>
> > myfiles = os.listdir("../")
> > print myfiles
>
> > for afile in myfiles:
> >     print afile
> >     if os.path.isfile(afile):
> >         print afile, "___file"
> >     if os.path.isdir(afile):
> >         print afile, "___dir"
> >     print
> > ------------
>
> > Here is what's in the directory:
>
> > ----------
> > $ ls -al ../
>
> > total 2576
> > drwxr-xr-x    8 nnn  nnn      272 Jul  1 03:03 .
> > drwxr-xr-x   25 nnn  nnn      850 Jul  1 01:34 ..
> > -rw-r--r--    1 nnn  nnn     6148 Jul  1 03:02 .DS_Store
> > -rw-r--r--    1 nnn  nnn  1300000 Jun 27 14:02 aaa.txt
> > drwxr-xr-x   55 nnn  nnn     1870 Jul  1 03:09 dir1
> > -rwxrwxrwx    1 nnn  nnn      263 Jun 27 22:40 mytest.py
> > -rw-r--r--    1 nnn  nnn        0 Mar  4 16:15 scratch.txt
> > -rw-r--r--    1 nnn  nnn      275 Apr 11 03:40 xmlFile.xml
> > ------------
>
> Yes, but what does 'ls -al .' show you? You didn't put any kind of path in
> your calls to isfile/isdir, so you are checking for the existence of
> files/directories called '.DS_Store' etc. in the *current* directory, not
> the one above. From your output I'd guess you have .DS_Store and aaa.txt
> files but the other names are not duplicated.

Thanks.