REALLY need help with iterating a list.
gagsl-py2 at yahoo.com.ar
Mon Jun 11 22:43:37 CEST 2007
En Mon, 11 Jun 2007 17:11:23 -0300, Radamand <radamand at gmail.com> escribió:
> On Jun 11, 1:23 pm, Fredrik Lundh <fred... at pythonware.com> wrote:
>> here's a simple variation of that, which is a bit more efficient, and
>> perhaps also a bit easier to use in the general case:
>> while serverlist:
>> still_active = 
>> for server in serverlist:
>> pinger = ping[server]
>> if pinger.returncode is None:
>> pingresult[server] = pinger.stdout.read()
>> pingreturncode[server] = pinger.returncode
>> serverlist = still_active
> Thats an interesting approach but, if the returncode for a given
> server is None say, 20 times in a row you will have append'ed that
> server to the list 20 times, i suppose you could check the list to see
> if its already there but thats a bit kludgey...
Read the code again and notice that there are TWO lists involved. There is
at most one append per server - unless there are duplicates in the
original list, the new list won't have any.
> also, the line "pinger = ping[server]" would have to be extracted from
> this loop otherwise your going to ping the same server repeatedly
> until it answers...
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