subexpressions
Steven D'Aprano
steve at REMOVE.THIS.cybersource.com.au
Sat Jun 2 16:05:17 CEST 2007
On Sat, 02 Jun 2007 05:54:51 -0700, Steve Howell wrote:
>>
>> def f(x): y = x*x; return sin(y)+cos(y);
>>
>
> Although I know valid trigonometry is not the point of
> this exercise, I'm still trying to figure out why
> anybody would ever take the square of an angle.
> What's the square root of pi/4 radians?
Approximately 0.886 radians. It corresponds to the angle of a point on the
unit circle quite close to (sqrt(2/5), sqrt(3/5)), or if you prefer
decimal approximations, (0.632, 0.775).
Angles are real numbers (in the maths sense), so sqrt(pi/4) radians is
just as reasonable an angle as pi/4 radians. Both are irrational numbers
(that is, can't be written exactly as the ratio of two integers).
--
Steven
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