Q: listsort and dictsort - official equivalents?

[Neville D]

Choice answer.  It exactly hit the mark.

I implemented "sorted" as follows:

#!/usr/bin/env python
d=dict(zip("cba",(2,1,3)))
for k in sorted(d,key=lambda k: d[k]): print k,d[k]

Output:
b 1
c 2
a 3

I am glad I asked.  Now I know.

Thanᚷ
NevilleDNZ

On Wed, 2007-06-20 at 02:57 +0200, BJörn Lindqvist wrote:
> You can even sort by the gid:
> 
> for group in sorted(open("/etc/group"), key = lambda x: int(x.split(':')[2])):
>     print group,

-- 
Neville D - NZ
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