Floating Number format problem
John Machin
sjmachin at lexicon.net
Tue Jun 12 06:43:22 EDT 2007
On Jun 12, 8:04 pm, Marc Christiansen <use... at solar-empire.de> wrote:
> Gabriel Genellina <gagsl-... at yahoo.com.ar> wrote:
> > En Tue, 12 Jun 2007 05:46:25 -0300, <kelvin.... at gmail.com> escribió:
>
> >> On 6 12 , 3 16 , ici <iltch... at gmail.com> wrote:
> >>> On Jun 12, 10:10 am, <kelvin.... at gmail.com> wrote:
>
> >>> > How could I format the float number like this: (keep 2 digit
> >>> > precision)
> >>> > 1.002 => 1
> >>> > 1.12 => 1.12
> >>> >>> print "%.02f" % (2324.012)
> >>> 2324.01
>
> >> But in these case:
>
> >>>>> print '%.02f'%1.002
> >> 1.00
> >>>>> print '%.02f'%1.00
> >> 1.00
>
> >> I just expect it to output "1" , but these way will output 1.00
>
> > def my_formatter_ommitting_trailing_zeroes(value):
> > result = '%.2f' % value
> > if result[-3:]=='.00': result = result[:-3]
> > return result
>
> > for f in [1.0, 1.002, 1.12, 1.567, 2324.012]:
> > print "%g -> %s" % (f, my_formatter_ommitting_trailing_zeroes(f))
>
> Or:
>
> def my_other_formatter_ommitting_trailing_zeroes(value):
> result = '%.2f' % value
> return result.rstrip('0.')
>
> my_other_formatter_ommitting_trailing_zeroes(1.102) == "1.1"
Marc, thanks for coming, but:
>>> my_other_formatter_ommitting_trailing_zeroes(100.00)
'1'
>>>
What does the OP want to happen with 1.2? I suspect he wants '1.2',
not '1.20'
Looks like a variation of Marc's idea will do the business:
>>> values = [100.0, 1.0, 1.2, 1.002, 1.12, 1.567, 2324.012]
>>> [('%.02f' % x).rstrip('0').rstrip('.') for x in values]
['100', '1', '1.2', '1', '1.12', '1.57', '2324.01']
Howzat?
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