a =
[0,1,2,3,4,2,8,9]
# method
1
print [i for i in xrange(len(a)) if
a[i]==2]
def
where(a,val):
return [i for i in xrange(len(a)) if
a[i]==val]
# method
2
print
where(a,2)
vorticitywolfe at gmail.com wrote:
> On Mar 18, 10:48 pm, bearophileH... at lycos.com wrote:
>
>> vorticitywo:
>>
>>
>>> Is there a function in Python analogous to the "where" function in
>>> IDL?
>>>
>> Python gives very elastic syntax, you can simply do:
>>
>> data = [0,1,2,3,4,2,8,9]
>> print [pos for pos, el in enumerate(data) if el==2]
>>
>> Bye,
>> bearophile
>>
>
> Thank you both, a little more cumbersome than I expected, but it does
> the job! Thanks!
>
>
--
Shane Geiger
IT Director
National Council on Economic Education
sgeiger at ncee.net | 402-438-8958 | http://www.ncee.net
Leading the Campaign for Economic and Financial Literacy
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