os.path.basename() - only Windows OR *nix?

Bruno Desthuilliers bdesth.quelquechose at free.quelquepart.fr
Wed Mar 14 21:47:10 CET 2007


Thomas Ploch a écrit :
> Hello,
> 
> I have a cgi script that handles fileuploads from windows and *nix
> machines. i need os.path.basename(filename) to get the pure filename.
> 
> For *nix, thats not a problem, but for windows, it always returns the
> full path:
> 
> 
> 
> #/usr/bin/env python
> 
> import cgi, os
> import cgitb; cgitb.enable()
> 
> form = cgi.FieldStorage()
> filename = os.path.basename(form['uploadfile'].filename)
> 
> print 'Content-Type: text/html\n\n'
> print filename
> 
> 
> 
> -----------------
> 
> For 'C:\text\text.txt', the output is 'C:\text\text.txt', which should
> be 'text.txt', the same happens for 'C:\\text\\text.txt'. I think its
> the escapes that makes python not splitting it. All Unix style paths get
> converted the right way.

Let me guess : your cgi script is running on *n*x ?-)

> Is there an easy way around this,

Probably.

 >>> fnames = "C:\\dir\\data.ext", "/dir/data.txt", "dir:data"
 >>> import ntpath, posixpath, macpath
 >>> def basename(filename):
...     for m in ntpath, posixpath, macpath:
...             if m.sep in filename:
...                     return m.basename(filename)
...     else:
...             # XXX
...             raise SomeException('could not do the job')
...
 >>> for f in fnames:
...     print f, basename(f)
...
C:\dir\data.ext data.ext
/dir/data.txt data.txt
dir:data data
 >>>

Might need some improvements, but you get the idea...

HTH



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