[B,IX] = sort(A,...) - Order for sort()-function

[Maric Michaud]

Orlando Döhring a écrit :
>  
...
> A = [ 3 7 5
>       0 4 2 ];
>  
> # in Python: A = [[3,7,5],[0,4,2]]
>  
> [B,IX] = sort(A,2)
>  
> # sort by rows
> 
> B =
>      3     5     7
>      0     2     4
> 
> IX =
>      1     3     2
>      1     3     2
>  
> # first line: 3 was formerly in the first position, 5 formerly in 
> position 3, 7 formerly in position 2
> # second line: similiarly
>  
>  

Like this :

In [122]: l=[[3,2,1], [4,6,5,0]]

In [123]: from operator import itemgetter

In [124]: [ list(sorted(enumerate(e), key=itemgetter(1))) for e in l ]
Out[124]: [[(2, 1), (1, 2), (0, 3)], [(3, 0), (0, 4), (2, 5), (1, 6)]]

except the old position is the first element of each tuple, you may have 
the same order with this one :


In [126]: [ list((pos, elt) for pos, elt in sorted(enumerate(e), 
key=itemgetter(1))) for e in l ]
Out[126]: [[(1, 2), (2, 1), (3, 0)], [(0, 3), (4, 0), (5, 2), (6, 1)]]