How to evaluate the code object returned by PyParser_SimplePa rseString function?

Borse, Ganesh ganesh.borse at credit-suisse.com
Fri Nov 16 12:54:57 CET 2007


Thanks this is helpful.

-----Original Message-----
From: Gabriel Genellina [mailto:gagsl-py2 at yahoo.com.ar] 
Sent: 15 November 2007 12:26
To: python-list at python.org
Subject: Re: How to evaluate the code object returned by PyParser_SimplePa rseString function?

En Wed, 14 Nov 2007 23:20:14 -0300, Borse, Ganesh <ganesh.borse at credit-suisse.com> escribió:

> Py_CompileString takes the source code from file, isn't it?
> As can be seen from the syntax of this function: PyObject* 
> Py_CompileString(char *str, char *filename, int start)
>
> I want to parse the code which is in memory - loaded from database.
> In that case, may I know, how to use the Py_CompileString?

The first argument is the actual source code string, a char*; the filename argument is only used to generate pretty error messages, you may pass in some meaningful name or '<string>'.

> If it is mandatory to read from file for this function?
> Reading from file increases startup time of my application.
> So, I was thinking of using PyParser_SimpleParseString, which takes 
> the code to be parsed in the "char*" format. Quit suitable to my need.

No, both Py_CompileString and PyParser_SimpleParseString take the same first argument, a char* with the source code.

> Can I use the output of the function PyParser_SimpleParseString as 
> input to PyEval_EvalCode?

Not directly, you must compile the parsed input first. See pythonrun.c for examples, but you will end duplicating what Py_CompileString already does.

--
Gabriel Genellina



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