Last value of yield statement

John Machin sjmachin at lexicon.net
Wed Oct 10 13:05:28 CEST 2007


On 10/10/2007 8:19 PM, Shriphani wrote:
> Hello all,
> 
> Let us say I have a function like this:
> 
> def efficientFiller(file):
>         worthless_list = []
>         pot_file = open(file,'r')
>         pot_file_text = pot_file.readlines()
>         for line in pot_file_text:
>                 if line.find("msgid") != -1:
>                         message_id = shlex.split(line)[1]
>                         if message_id in dictionary:
>                                 number = pot_file_text.index(line)
>                                 corresponding_crap =
> dictionary.get(message_id)
>                                 final_string = 'msgstr' + " " + '"' +
> corresponding_crap + '"' + '\n'
>                                 pot_file_text[number+1] = final_string
>                                 yield pot_file_text
> 
> efficient_filler =  efficientFiller("libexo-0.3.pot")
> new_list = list(efficient_filler)
> print new_list
> 
> 
> 
> I want to plainly get the last value the yield statement generates.
> How can I go about doing this please?
> 

I don't think that 'efficient' and 'plainly' mean what you think they 
mean. However to answer your question:

     new_list[-1] if new_list else None

BTW I get the impression that the yield statement yields the whole 
pot_file_text list each time, so that new_list will be a list of lists; 
is that intentional?



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