Can you determine the sign of the polar form of a complex number?

[J. Robertson]

schaefer.mp at gmail.com wrote:
> Just to clarify what I'm after:
> 
> If you plot (-3)^n where n is a set of negative real numbers between 0
> and -20 for example, then you get a discontinuos line due to the
> problem mentioned above with fractional exponents. 
>
> .. 
> 

It looks like you crash-landed in imaginary space, you may want to think 
again about what you're up to :-)  Complex numbers are not positive or 
negative, as such.

If you want to obtain a continuous curve, then take the real part of the 
complex number you obtain, as in "((-3+0j)**(-x)).real", it will fit 
with what you obtain for integers.