determining fully qualified package & class name

patrimith paddysmith at
Thu Oct 11 20:18:33 CEST 2007

Hi List,

I am used to the following with Java:

import some.package.MyClass;
name = MyClass.class.getName();

The value for name will be "some.package.MyClass".

For Python, I find:

from some.package.myclass import MyClass
name = MyClass.__name__

The value for  name will be "MyClass"

Is there a comparable way to get the fully qualified name (package, module,
and class name) in Python?

Patrick Smith
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