greatest and least of these...
Marc 'BlackJack' Rintsch
bj_666 at gmx.net
Tue Oct 23 12:48:24 EDT 2007
On Tue, 23 Oct 2007 11:56:33 -0400, Shawn Minisall wrote:
> I just wrote a program to let the user input a series of whole numbers
> and tell them which is least and which is greatest based off of a menu.
> However, the menu isn't kicking in after they pick a number. I included
> a while statement for a loop just for the menu and compared it to my
> other programs that have a similar setup and are working, but I'm
> stumped. Here's the program...
>
> def main():
>
> #define and initialize variables
> #choice as int
> choice = 0
> #number as int
> number = 0
>
> #intro
> print "WELCOME TO THE GREATEST AND LEAST NUMBER PROGRAM!"
> print
>
> #Menu loop
> while choice != 2:
> #display menu
> print "Please choose from the following menu: "
> print "1. Enter a number"
> print "2. Exit"
> print
>
> #prompt user for their menu choice
> choice = input("Enter your choice here: ")
>
> #if statements to determine which choice
> if choice == 1:
> nums = []
> while number >=0:
> nums.append(number)
> number = input("Please enter a number.")
Maybe you want to exchange those two last lines!?
> elif choice == 2:
> print "Have a great day!"
>
> if len(nums) > 0:
> print "The smallest number that you entered was:",min(nums)
> print "The largest number that you entered was:",max(nums)
> Also, if they quit the program with choice #2 and entered numbers, it
> should display the greatest and least of them. If they just started and
> didn't enter anything and want to quit, I get an error message saying
> UnboundLocalError: local variable 'nums' referenced before assignment.
> Isn't the if statement supposed to keep python from going there since if
> they didn't enter any input, the length of the list should just be zero.
Which list? If the branch for ``choice == 1`` isn't executed then the
list will never be created an the name `nums` doesn't exist.
Ciao,
Marc 'BlackJack' Rintsch
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