Last value of yield statement
khemkaamit at gmail.com
Wed Oct 10 13:02:41 CEST 2007
On 10/10/07, Shriphani <shriphanip at gmail.com> wrote:
> On Oct 10, 3:34 pm, Dustan <DustanGro... at gmail.com> wrote:
> > On Oct 10, 5:19 am, Shriphani <shripha... at gmail.com> wrote:
> > > Hello all,
> > > Let us say I have a function like this:
> > > def efficientFiller(file):
> > Note that you are shadowing the built-in variable 'file' here. Better
> > use 'filename', or something to that effect.
> > > worthless_list = 
> > > pot_file = open(file,'r')
> > > pot_file_text = pot_file.readlines()
> > > for line in pot_file_text:
> > > if line.find("msgid") != -1:
> > > message_id = shlex.split(line)
> > > if message_id in dictionary:
> > > number = pot_file_text.index(line)
> > > corresponding_crap =
> > > dictionary.get(message_id)
> > > final_string = 'msgstr' + " " + '"' +
> > > corresponding_crap + '"' + '\n'
> > > pot_file_text[number+1] = final_string
> > > yield pot_file_text
> > > efficient_filler = efficientFiller("libexo-0.3.pot")
> > > new_list = list(efficient_filler)
> > > print new_list
> > > I want to plainly get the last value the yield statement generates.
> > > How can I go about doing this please?
> Well the basic trouble is that the yield statement you see there
> causes it to print the list over and over again when a string
> containing "msgid" is found and the subsequent conditions are
> satisfied. I just want the last list the yield statement generates. I
> don't want the last element of the list generated. just the last
I may be being stupid but i really fail to understand that why would
you want to use 'yield' in such a scenario ?
Btw, the following line in your code may cause some unexpected
behavior (in case of duplicates):
number = pot_file_text.index(line)
You should rather use 'enumerate' .
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