recursion
Ian Clark
iclark at mail.ewu.edu
Thu Sep 13 12:14:42 EDT 2007
Neil Cerutti wrote:
> On 2007-09-13, Gigs_ <gigs at hi.t-com.hr> wrote:
>> Can someone explain me this
>>
>>>>> def f(l):
>> if l == []:
>> return []
>> else:
>> return f(l[1:]) + l[:1] # <= cant figure this, how is all sum at the end?
>
> In plain English, the above program says:
>
> The sum of the items in list l is zero if the list is empty.
> Otherwise, the sum is the value of the first item plus the sum of
> the rest of the items in the list.
Am I missing something? What does this have to do with summing?
>>> def f(l):
... if l == []:
... return []
... else:
... return f(l[1:]) + l[:1]
...
>>> f([1, 2, 3, 4])
[4, 3, 2, 1]
Ian
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