Help me understand this script

[Gerardo Herzig]

Ryan J Nauman wrote:

>Can someone help me understand this script please?
>I understand everything except for the anagram function.  Could you break 
>it down into more than 1 line of code for me or explain it? (I understand 
>WHAT it does but HOW?) Thanks.
>
>Script >>
>
>###
># SCRABBLE.PY
>#
># purpose: 
>#       find usable "bingos" based on your rack
>#
># usage:
>#       python scrabble.py eilsnsy
>#
># output:
># Straight anagrams: 
>#  linseys
>#  lysines
># Possible other words: 
># + B
>#   sensibly
>#+ K
>#   skylines
>#+ V
>#   sylvines
>###
># Scrabble is a registered trademark of J. W. Spear & Son PLC and 
># Hasbro Inc. Any and all uses of the word "Scrabble" in this code
># refers to this trademark.
>#
># This code is not affiliated with any company.
>###
>
>import sys
>
>WORDS = [ i.rstrip ().lower() for i in file ('c:\python25\TWL06.txt') ]
># you can download the current TWL and/or SOWPODS dictionaries from 
># http://67.19.18.90/twl.zip and http://67.19.18.90/sowpods.zip . 
># Update the file name above as appropriate if you want to use a "proper"
># Scrabble dictionary.
>
>
>
>def alphabetise(word):
>    x = [i for i in word]
>    x.sort()
> 
>    return "".join(x)
>
>def anagram(word):
>    wordLength = len(word)
>    sortedWord = alphabetise(word.lower())
>    return [i for i in WORDS if len(i) == wordLength and alphabetise(i) == 
>sortedWord]
>
>for word in sys.argv[1:]:
>    print "Straight anagrams: "
>    for i in anagram(word):
>        print "  " + i
>    print "Possible other words: "
>    for i in "ABCDEFGHIJKLMNOPQRSTUVWXYZ":
>        a = anagram(i + word)
>        if a:
>            print "+", i
>            for h in a:
>                print "  ", h
>
><< End script
>  
>
I guess the difficult part remains in the last line. (Untested code bellow)
[code]

def anagram(word):
    resultValue = []
    wordLength = len(word)
    sortedWord = alphabetise(word.lower()) #not much to change until here
    for WORD in WORDS:
	if wordLength == len(WORD) and alphabetise(WORD) == sortedWord:
		resultValue.append(WORD)

    return resultValue

[/code]

Cheers.
Gerardo