frange() question

Tim Golden mail at timgolden.me.uk
Thu Sep 20 15:21:51 CEST 2007


George Trojan wrote:
> A while ago I found somewhere the following implementation of frange():
.
.
.
>      return (limit1 + n*increment for n in range(count))
> 
> I am puzzled by the parentheses in the last line. Somehow they make 
> frange to be a generator:

> But I always thought that generators need a keyword "yield". What is 
> going on here?

That's what's known as a generator expression:

http://docs.python.org/ref/genexpr.html
http://www.python.org/dev/peps/pep-0289/

TJG



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