super() doesn't get superclass

Neil Cerutti horpner at yahoo.com
Wed Sep 19 14:58:48 CEST 2007


On 2007-09-19, Hrvoje Niksic <hniksic at xemacs.org> wrote:
> Ben Finney <bignose+hates-spam at benfinney.id.au> writes:
>
>> Hrvoje Niksic <hniksic at xemacs.org> writes:
>>
>>> class X(Y):
>>>   def foo(self):
>>>     super(X, self).foo()
>>> 
>>> ...there is in fact no guarantee that super() calls a superclass of
>>> X.  However, it is certainly guaranteed that it will call a superclass
>>> of type(self).
>>
>> Not even that. It could call *any class in the inheritance
>> hierarchy*,
>
> The inheritance hierarchiy is populated by the various (direct
> and indirect) superclasses of type(self).
>
>> depending on how the MRO has resolved "next class". Even one that is
>> neither an ancestor nor a descendant of X.
>
> My point exactly.  superclass of X is not the same as
> superclass of type(self).  Super iterates over the latter,
> where you expect the former.

I can't blame a person for thinking that the call

  super(A, self)

is taking the superclass of A. A is perhaps too prominently
placed.

-- 
Neil Cerutti



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