can Python be useful as functional?
Rustom Mody
rustompmody at gmail.com
Tue Sep 18 08:21:28 CEST 2007
On 9/18/07, Alex Martelli <aleax at mac.com> wrote:
> Rustom Mody <rustompmody at gmail.com> wrote:
>
> > Can someone help? Heres the non-working code
> >
> > def si(l):
> > p = l.next()
> > yield p
> > (x for x in si(l) if x % p != 0)
> >
> > There should be an yield or return somewhere but cant figure it out
>
> Change last line to
>
> for x in (x for x in si(l) if x % p != 0): yield x
Thanks but why does
(yield(x) for x in si(l) if x % p != 0)
not work? I would have expected generator expression to play better
with generators.
More generally, if one wants to 'splice in' a generator into the body
of a generator, is there no standard pythonic idiom?
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