Python 3.0 new integer division
jgardner at jonathangardner.net
Tue Apr 8 18:24:57 CEST 2008
On Apr 8, 9:13 am, "Hutch" <A... at MCHSI.COM> wrote:
> We now have a float result when two integers are divided in the same mannor
> as 2.4 or 2.5.
> I can handle that and use the Floor division but a simple question.
> Why in the world would you round down the last presented digit to a 6
> instead of just leaving it along as an 8.
> For some reason rounding down for a float in Python does not seem correct.
> IDLE 3.0a4
> >>> 12345678901234567890123456789012345678901234567890/345
> >>> 12345678901234567890123456789012345678901234567890//345
> 35784576525317586000000000000000000000000000000 == 3.5784576525317586e+46
Floats are weird that way. Part of the problem is you are representing
a decimal number (base 10) in binary (base 2). The other part is that
you can't increment floats by a very tiny amount. In other words, a +
b = a for floats when b is sufficiently small but not zero.
Blame floats, not Python.
If you want precision with fractions, you should be using the Decimal
type, which uses a rational. A rational, if you recall from your math
classes, is one integer divided by another.
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