sjmachin at lexicon.net
Tue Apr 22 23:50:10 CEST 2008
Joe Riopel wrote:
> On Tue, Apr 22, 2008 at 4:55 PM, DataSmash <rdh at new.rr.com> wrote:
>> I have a list that looks like this:
>> roadList = ["Motorways","Local","Arterial"]
>> I want to apply some code so that the output looks like this:
>> How can this be done with the LEAST amount of code?
> Not sure if it's LEAST amount of code, or the best, but it works.
It's definitely not the least (see below) and it doesn't work -- it puts
a ; after the last list item.
>>>> li = ["Motorways","Local","Arterial"]
>>>> '\"%s\"' % (''.join(['%s;' % (x,) for x in li]),)
That is littered with redundant punctuation. Removing it:
>>> '"%s"' % ''.join('%s;' % x for x in li)
Note: that would need the  put back for Python < 2.4. But in any case
we can further reduce it like this:
>>> '"%s;"' % ';'.join(li)
Now we have minimal, legible code which works on Python back to 2.1 at
least and is only one thump of the Delete key away from what the OP
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