basic python question about for loop

jmDesktop needin4mation at gmail.com
Wed Apr 9 17:03:30 EDT 2008


On Apr 9, 4:59 pm, "Reedick, Andrew" <jr9... at ATT.COM> wrote:
> > -----Original Message-----
> > From: python-list-bounces+jr9445=att.... at python.org [mailto:python-
> > list-bounces+jr9445=att.... at python.org] On Behalf Of jmDesktop
> > Sent: Wednesday, April 09, 2008 4:51 PM
> > To: python-l... at python.org
> > Subject: basic python question about for loop
>
> > >From the Python.org tutorial:
>
> > >>> for n in range(2, 10):
> > ...     for x in range(2, n):
> > ...         if n % x == 0:
> > ...             print n, 'equals', x, '*', n/x
> > ...             break
> > ...     else:
> > ...         # loop fell through without finding a factor
> > ...         print n, 'is a prime number'
> > ...
> > 2 is a prime number
> > 3 is a prime number
> > 4 equals 2 * 2
> > 5 is a prime number
> > 6 equals 2 * 3
> > 7 is a prime number
> > 8 equals 2 * 4
> > 9 equals 3 * 3
>
> > first time 2 mod 2, 2/2, no remainder == 0, what am I doing wrong?
> > Why did it fall through?
>
> a) 2 is prime, so nothing is wrong.
>
> b) Range isn't doing what you think it's doing:
>
> >>> print range(2,2)
> []
> >>> print range(2,3)
> [2]
> >>> print range(2,4)
> [2, 3]
> >>> print range(2,5)
>
> [2, 3, 4]
>
>
>
> >>> print range(1,1)
> []
> >>> print range(1,2)
> [1]
> >>> print range(1,3)
> [1, 2]
>
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>
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So what is n and x in the first iteration?  Sorry.  I'm trying.



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