function that accepts any amount of arguments?

[Paul McNett]

globalrev wrote:
> if i want a function that can take any amount of arguments how do i
> do?

Put an asterisk before the argument name.


> lets say i want a function average that accepts any number of integers
> and returns the average.

def avg(*args):
   return sum(args) / len(args)

There are some dangers (at least two glaring ones) with this code, 
though, which I leave as an exercise for the reader.

:)

Paul