newb loop problem

Larry Bates larry.bates at websafe.com`
Wed Aug 13 00:35:09 EDT 2008


Dave wrote:
> Hey there, having a bit of problem iterating through lists before i go
> on any further, here is
> a snip of the script.
> --
> d = "a1 b1 c1 d1 e1 a2 b2 c2 d2 e2 a3 b3 c3 d3 e3 a4 b4 c4 d4 e4 a5 b5
> c5 d5 e5"
> inLst = d.split()
> hitLst = []
> 
> hitNum = 0
> stopCnt = 6 + hitNum
> 
> for i in range(hitNum,len(inLst), 1):
> 	if i == stopCnt: break
> 	hitLst.append(inLst[i])
> 
> print hitLst
> --
> $ python helper.py
> ['a1', 'b1', 'c1', 'd1', 'e1', 'a2']
> 
> 
> This works fine for my purposes, what I need is an outer loop that
> goes through the original list again and appends my next request.
> 
> ie.
> 
> hitNum = 5
> 
> which will return:
> 
> ['a2', 'b2', 'c2', 'd2', 'e2', 'a3']
> 
> and append it to the previous one.
> 
> ie:
> 
> ['a1', 'b1', 'c1', 'd1', 'e1', 'a2']
> ['a2', 'b2', 'c2', 'd2', 'e2', 'a3']
> 
> 
> not really sure how to do this right now though, been trying several
> methods with no good results.
> 
> btw, just creating lagged values (sort of shift registers) on the
> incoming signal
> 
> Many thanks,
> 
> Dave

Dave,

You are going to need to supply us with more info to help.

1) Are you always going to want to get 6 elements from the list
2) Are you always going to want to step by 5 elements as your offset each time 
through the outer loop?
3) Is your requirement just to split inLst into equal length lists and append 
them together into a list?

Depending on your answers this might be quite easy.

-Larry



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